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Upper primary school mathematics question UPQ579
Fatimah were given equal number funfair coupons to sell. They did not manage to completely sell all their share of coupons. Sarin sold 7 times as many coupons as Hairu and was left with 15 unsold coupons . 1/2 of the coupons sold by Fatimah was 5 more than those by Hairu. The 3 of them sold a total of 260 funfair coupons.
a. How many coupons did Fatimah sell?
b. How many coupons did each of them receive?
Solution:
a. The total number of coupons sold = 260
From the model,
10 units + 10 = 260
10 units = 250
1 units = 25 coupons
The number that Fatimah sold = 2 × 25 + 10 = 60 coupons
b. The number of coupons each of them has = 7 × 25 + 15 = 190 coupons
Alternative solution:
Half of Fatimah sold was 5 more than Hairu sold,
Fatimah : Hairu = (2U+10) : 1U
Sarin sold 7 times as many as Hairu sold,
Sarin : Hairu = 7U : 1U
The ratio of number of coupons sold,
Sarin : Hairu : Fatimah = 7U : 1U : (2U+10)
In total, 7U + 1U + 2U + 10 = 10U + 10
Given the total number of ticket sold = 260
Hence,
10U = 250
1U = 25
a. The number of coupons sold by Fatimah = 2 × 25 + 10 = 60
b. The number of coupons each of them has at first
= 7 × 25 + 15 = 190
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