Sarin learns Perimeter, Area and Volume in school part 120 (Math Question)

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The blog postings are about the Singapore Math. The readers can learn from the postings about Solving Singapore Primary School Mathematics. The blog presents the Math Concept, the Math Questions with solutions that teaches in Singapore Primary Schools. You or the kids can acquire the skill of dealing with the Math Modeling, the Math Problem Solving and the Problem Sum from Lower Primary School to Upper Primary School level after reading the blog postings. This posting is an upper primary school math question on Shapes, aerimeter and Area.

You can read posting Sarin learns Perimeter, Area and Volume in school (Math Concept) to learn the concept of volume.

Read also the posting on Sarin learns Shapes and Solids in school (Math Concept) to know about solid.

Challenge yourself with the question before look out for the given solution‼!

Upper primary school mathematics question UPQ577

The figure below is made up of 6 identical quadrants with radius 4 cm.

a.         What is the perimeter of the orange region of the figure?

b.         What is the area of the orange region of the figure?

            (Express your answer in term of π)

 

The rectangle papers are identical and the length is 3 time of the breadth.

If the total area of the figure was 648 m2, what was the length of the rectangle paper?

Solution:

a.         The radius = 4 cm

            The length of the arc of 6 identical quadrants

            = 1.5 times of the perimeter of the circle with radius

            = 1.5 × 2 × π × 4

            = 12 π  cm

            The perimeter of the orange region

            = 4 + 4 + 12π

            = (8 + 12π) cm

b.         The area of 2 squares = 2 × 4 × 4 = 32 cm2

            Refer to the above figure,

            The area of A

            = the area of the square – the area of the quadrant

            = 4 × 4 –

            = (16 – 4π) cm2

            The area of the orange region

            = 6 times of the area of A + the area of 2 squares

            = 6 × (16 – 4π) + 32

            = (128 – 4π) cm2

   More Questions on Area and Perimeter. Click here….

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