Sarin’s family celebrating Hari Raya Puasa part 23 (Math Question)

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The blog postings are about the Singapore Math. The readers can learn from the postings about Solving Singapore Primary School Mathematics. The blog presents the Math Concept, the Math Questions with solutions that teaches in Singapore Primary Schools. You or the kids can acquire the skills to deal with the Math Modeling, the Math Problem Solving and the Problem Sum from Lower Primary School to Upper Primary School level after reading the blog postings. This posting is an upper primary school math question on AlgebraRatio and Problem Sum.

You can read the postings on Sarin’s family celebrating Hari Raya Puasa and Sarin’s family and Ramadan in Welcome page about story of Sarin’s family during Ramadan and Hari Raya Puasa.

Read the posting on Sarin learns Symbol, Algebra and Equation in school (Math Concept) to understand the concept of Algebra.

To read also the posting on Sarin learns concept of ratio in school to understand the concept of Ratio.

Challenge yourself with the question before look out for the given solution !!!

Upper primary school mathematics question UPQ573

Fatimah prepared some gifts for celebrating Hari Raya. She used some string to tie 24 small size gifts. As well she used the same amount of string to tie 16 large size gifts. Each large size gift used 70 cm more string than small size gift. How many metres of string did Fatimah used altogether?

upq573-1

Solution:

            Using Algebra concept,

            The length of string used to tie one small size gift = 1U

            The length of string used to tie one large size gift = 1U + 70

            There were 24 small size gifts,

            The length of the string to tie all the small size gifts = 24U

            There were 16 large size gifts,

            The length of the string to tie all the large size gifts = 16U + 1120

            Since, Fatimah used the same amount of string for small and large size gifts,

            24U = 16U + 1120

            8U = 1120

            1U = 140 cm

            The total amount of string used for both small and large size gifts

            = 140 × 24 × 2

            = 6720 cm

            = 67.2 m

Alternative solution:

            Same amount of string used for small and large size gifts,

            The ratio of the string use for a small size gift to a large size gift

            S : L = 16 : 24 = 2 : 3

            The math model,

upq573-2

            From the model,

            1 unit = 70 cm

            The length of string used to tie one small size gift = 2 × 70 = 140

            The length of string used to tie the small size gifts = 24 × 140 = 3360 cm

            Same amount of string used for large size gifts,

            The total amount of string used

            = 2 × 3360

            = 6720 cm

            = 67.2 m

More Questions on Problem Sum. Click here….

More Questions on Ratio. Click here….

More Question on Algebra. Click here…..

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