# Sarin learns Perimeter, Area and Volume in school part 111 (Math Question)

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The blog postings are about the Singapore Math. The readers can learn from the postings about Solving Singapore Primary School Mathematics. The blog presents the Math Concept, the Math Questions with solutions that teaches in Singapore Primary Schools. You or the kids can acquire the skill of dealing with the Math Modeling, the Math Problem Solving and the Problem Sum from Lower Primary School to Upper Primary School level after reading the blog postings. This posting is an upper primary school math question on Ratio and Volume

You can read posting Sarin learns Perimeter, Area and Volume in school (Math Concept) to learn the concept of area.

Read also the posting on Sarin learns Shapes and Solids in school (Math Concept) to know about shapes.

Read the posting on Sarin learns ratio in school (Math Concept) to learn about concept of Ratio.

Challenge yourself with the question before look out for the given solution‼!

Upper primary school mathematics question UPQ520

Two rectangular tanks are shown below. Tank A is initially filled with water up to 5/8 of the capacity. The Tank B is empty. A tube is then use to transfer the water from Tank A into Tank B. What is the volume of the water in Tank B when both of the tanks have the same water level?

Solution:

Total volume of water = 20 × 18 × 40 × 5/8 = 9000 cm3

The total base area = 20 × 18 + 15 × 16 = 600 cm3

The water level in both tanks = 9000 ÷ 600 = 15 cm

The volume of water in tank B = 16 × 15 × 15 = 3600 cm3

Alternative Solution:

The total amount of water = 20 × 18 × 40 × 5/8 = 9000 cm3

The final height of water in both tanks are the same

The volume of water in the tanks will based on their base area of the tanks

The ratio of based area of the two tanks,

Tank A : Tank B = 20 × 18 : 16 × 15 = 3 : 2

The volume ratio of the tanks,

Tank A : Tank B : Total volume : 3 : 2 : 5

5 units = 9000 cm3

1 unit = 1800 cm3

The volume of water in Tank B = 2 × 1800 = 3600 cm3