Sarin learns Perimeter, Area and Volume in school part 110 (Math Question)


The blog postings are about the Singapore Math. The readers can learn from the postings about Solving Singapore Primary School Mathematics. The blog presents the Math Concept, the Math Questions with solutions that teaches in Singapore Primary Schools. You or the kids can acquire the skill of dealing with the Math Modeling, the Math Problem Solving and the Problem Sum from Lower Primary School to Upper Primary School level after reading the blog postings. This posting is an upper primary school math question on RatioShape and Area

You can read posting Sarin learns Perimeter, Area and Volume in school (Math Concept) to learn the concept of area.

Read also the posting on Sarin learns Shapes and Solids in school (Math Concept) to know about shapes.

Read the posting on Sarin learns ratio in school (Math Concept) to learn about concept of Ratio.

Challenge yourself with the question before look out for the given solution‼!

Upper primary school mathematics question UPQ517

ABC and ADE are two identical right angle triangles. AC is 6 cm. What is the area of Triangle CFE?




Since ABC and ADE are identical right angle triangles

AC = AD = 6 cm

The triangles ADF, ACF and CFE are equal in height

The ratio of their area is proportional with their base length

ADF : ACF : CFE = AD : AC : CE = 6 : 6 : 14 = 3 : 3 : 7

The area of triangle ADE = ½ × 6 × 20 = 60 cm2

13 units = 60 cm2

1 unit = 60/13 cm2

The area of the triangle CFE = 7 × 60/13 = 32.3 cm2

   More Questions on Area. Click here….

More Questions on Ratio. Click here….


4 responses »

    • Hi Pat,
      You are right, CE is equal to 14cm so the ratio should be 6:6:14 = 3:3:7. My original intention was AB = 26 cm and DB = CE = 26 – 6 = 20cm. But some how in the figure……
      I will keep the ratio to 3:3:7 for the question and update the working and the final solution.
      It is important to get the information accurate, thanks for your valuable feedback and keep coming.

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