# Sarin learns Perimeter, Area and Volume in school part 88 (Math Question)

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The blog postings are about the Singapore Math. The readers can learn from the postings about Solving Singapore Primary School Mathematics. The blog presents the Math Concept, Math Questions with solutions that teaches in Singapore Primary Schools. You or the kids can acquire the skill of dealing with Math Modeling, Math Problem Solving and Problem Sum from Lower Primary School to Upper Primary School level after reading the blog postings. This posting is an upper primary school math question on Algebra, Ratio and Area .

You can read posting Sarin learns Perimeter, Area and Volume in school(Math Concept) to learn the concept of perimeter and area.

Read also the posting on Sarin learns Shapes and Solids in school (Math Concept) to know about shapes.

Read the posting on Sarin learns Symbol, Algebra and Equation in school (Math Concept) to understand the concept of Algebra.

Also to read the posting on Sarin learns concept of ratio in school to understand the concept of Ratio.

Challenge yourself with the question before look out for the given solution‼!

Upper primary school mathematics question UPQ394

The perimeter of a rectangle is 72 cm. If the ratio of its length to its breadth is 3 : 1, find the area of the rectangle.

Solution:

Based on the ratio of length to breadth = 3 : 1

Perimeter = 72cm

Length plus breadth = 72 ÷ 2 = 36cm

4 units = 36

1 units = 9cm

Length = 3 × 9 = 27cm

The area of the rectangle = 9 × 27 = 243cm2

Alternative solution:

Using Algebra expression

Set B as the breadth of the rectangle

Based on the ratio of length to breadth = 3 : 1

The length of the rectangle = 3B

Perimeter of a rectangle = 2 × (3B + B) = 8B

In this case, perimeter of the rectangle = 72cm

The Breadth of the triangle = B = 72 ÷ 8 = 9cm

The Length of the rectangle = 3 × 9 = 27cm

The area of the rectangle = 9 × 27 = 243cm2