# Sarin learns Perimeter, Area and Volume in school part 84 (Math Question)

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The blog postings are about the Singapore Math. The readers can learn from the postings about Solving Singapore Primary School Mathematics. The blog presenting the Math Concept, Math Questions with solutions that teaches in Singapore Primary Schools. You or the kids can acquire the skill of dealing with Math Modeling, Math Problem Solving and Problem Sum from Lower Primary School to Upper Primary School level after reading the blog postings. This posting is an upper primary school math question on Shape and Area.

You can read posting Sarin learns Perimeter, Area and Volume in school(Math Concept) to learn the concept of perimeter and area.

Read also the posting on Sarin learns Shapes and Solids in school (Math Concept) to know about shapes.

Challenge yourself with the question before look out for the given solution‼!

Upper primary school mathematics question UPQ368

The figure below shows 2 identical regular hexagons overlapping each other. Each hexagon has an area of 216 cm2 each. Given that AB = BC, find the area of the yellow region.

Solution:

A regular hexagon is a 6 sided-ploygon that with each side equal in length and it is formed by 6 identical equilateral triangles

AB = BC, the overlapping area is area of 2 equaliteral triangles

The area of the hexagon = 216cm2

The area of one equilateral triangle = 216 ÷ 6 = 36cm2

The area of the yellow region = The area of 4 equilateral triangles = 4 × 36 = 144cm2