Sarin learns Perimeter, Area and Volume in school part 81 (Math Question)

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The blog postings are about the Singapore Math. The readers can learn from the postings about Solving Singapore Primary School Mathematics. The blog presenting the Math Concept, Math Questions with solutions that teaches in Singapore Primary Schools. You or the kids can acquire the skill of dealing with Math Modeling, Math Problem Solving and Problem Sum from Lower Primary School to Upper Primary School level after reading the blog postings. This posting is an upper primary school math question on Perimeter and Area.

You can read posting Sarin learns Perimeter, Area and Volume in school(Math Concept) to learn the concept of perimeter and area.

Challenge yourself with the question before look out for the given solution‼!

Upper primary school mathematics question UPQ344

Figure A, shown below, has an area of 768 cm2. It is made up of 4 similar rectangles. If the rectangles are re-arranged to form Figure B, find the perimeter of Figure B.

UPQ344-1

Solution:

UPQ344-2

            The length (L) of the rectangle is 3 times of the breadth (B)

            The area of one rectangle = 768 ÷ 4 = 192cm2

            3B × B = 192

            B × B = 64 = 8 × 8

            The breadth of the rectangle = 8cm

            The length of the rectangle = 3 × 8 = 24cm

            The perimeter of figure B = 24 × 8 = 192cm

 More Questions on Perimeter and Area. Click here…. 

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