Sarin learns Perimeter, Area and Volume in school part 76 (Math Question)

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The blog postings are about the Singapore Math. The readers can learn from the postings about Solving Singapore Primary School Mathematics. The blog presenting the Math Concept, Math Questions with solutions that teaches in Singapore Primary Schools. You or the kids can acquire the skill of dealing with Math Modeling, Math Problem Solving and Problem Sum from Lower Primary School to Upper Primary School level after reading the blog postings. This posting is an upper primary school math question on Area.

You can read posting Sarin learns Perimeter, Area and Volume in school(Math Concept) to learn the concept of perimeter and area.

Challenge yourself with the question before look out for the given solution‼!

Upper primary school mathematics question UPQ328

ABCD is a rectangle. Area X is 5 cm2 greater than Area Y. Find the length of BC.

UPQ328-1

 

 

 

Solution:

            The area of the triangle EDC = 10 × 15 ÷ 2 = 75cm2

            Area X is greater than Area Y by 5cm2

            By removing 5cm2 from the triangle EDC give the area of the rectangle ABCD

            The area of rectangle ABCD = 75 – 5 = 70cm2

            The length BC = 70 ÷ 15 = 4 10/15 = 4 2/3cm

More Questions on Area. Click here….

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