Sarin’s family and Ramadan Part 9 (Math Question)

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The blog postings are about the Singapore Math. The readers can learn from the postings about Solving Singapore Primary School Mathematics. The blog presenting the Math Concept, Math Questions with solutions that teaches in Singapore Primary Schools. You or the kids can learn the skills of dealing with Math Modeling, Problem Sum from Lower Primary School to Upper Primary School level after reading the postings. This posting is an upper primary school math question on Perimeter, Area and Problem Solving.

You can read the posting on Sarin’s family and Ramadan and Sarin’s family celebrating Hari Raya Puasa in Welcome page about story of Sarin’s family during Ramadan and celebrating Hari Raya Puasa.

You shuold read the posting on Sarin learns Perimeter, Area and Volume in school(Math Concept) to learn the concept of Area.

Challenge yourself to solve the question before look out for the given solution‼

Upper primary school mathematics question UPQ259

After tidying up the house, Fatimah’s mother sews a piece of carpet to use during Hari Raya Puasa.  The carpet has a brown outskirt with 10cm wide and fills with yellow and purple circles with identical size. A green cloth is used as the centre piece of the full carpet. The figure below showed a quarter of the carpet design. If there are 38 circles in total in a quarter of the carpet,

a) Find the outskirt area that is not covered by the circles.

b) Find the perimeter and area of the green cloth.

Solution:

            Base on a quarter of the carpet.

            The length of a quarter of brown outskirt = 10 × 38 ÷ 2 ÷ 2 = 95cm

            The area of a quarter of the brown outskirt = 95 × 10 = 950cm2

            The radius of each circle = 10 ÷ 4 =2.5cm

            The area of 38 circles = 38 × π × 2.5 × 2.5 = 38 × 3.14 × 2.5 × 2.5 = 745.75cm2

            The area of a quarter of the outskirt not cover with circles = 950 – 745.75 = 204.25cm2

            The area of the outskirt not cover with circles = 4 × 204.25 = 817cm2

            Base on a quarter of the carpet,

            Consider only the inner ring circles,

            Set the number of inner ring circles as X and Y respectively

            X + Y = (38 – 4) ÷ 2 = 17

            The length of (X + Y) = 17 × 10 ÷ 2 = 85cm

            The perimeter of the green cloth = 4 × 85 = 340cm

            Assume maximum size for the carpet

            17 ÷ 2 = 8R1

            X = 8 and Y = 9

            The length of X = 8 × 10 ÷ 2 = 40cm

            The length of Y = 9 × 10 ÷ 2 = 45cm

            The area of a quarter of the green cloth = 40 × 45 = 1800cm2

            The area of the green cloth = 4 × 1800 = 7200cm2

       More Questions on Problem Sum. Click here…..

More Questions on Area. Click here….

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