The blog postings are about the Singapore Math. The readers can learn from the postings about Solving Singapore Primary School Mathematics. The blog presenting the Math Concept, Math Questions with solutions that teaches in Singapore Primary Schools. You or the kids will learn to deal with Math Modeling, Problem Sum from Lower Primary School to Upper Primary School level. This posting is an upper primary school math question on Circle, Area and Perimater.

You can read posting **Sarin learns Perimeter, Area and Volume in school(Math Concept) **to learn the concept of perimeter and area.

**Upper primary school mathematics question UPQ226**

The solid figure is made up of 4 quadrants of radius 20cm. Find the perimeter and area of the figure. (Take π = 3.14)

Solution:

The perimeter of the figure is 4 arcs of the quadrants = circumference of a circle.

The perimeter of the figure = π × 2 × 20 = 125.6 cm^{2}

The area of the figure is sum of the area of a quadrant and three time area of a quadrant and a square

The area of the figure = 3 × (20 × 20 – ¼ × π × 20 × 20) + ¼ × π × 20 × 20 = 572 cm^{2}^{ }