Sarin learns rate of change in school Part 4 (Math Question)

Standard

The blog postings are about the Singapore Math. The readers can learn from the postings about Solving Singapore Primary School Mathematics. The blog presenting the Math Concept, Math Questions with solutions that teaches in Singapore Primary Schools. You or the kids can learn deal with Math Modeling, Problem Sum from Lower Primary School to Upper Primary School level. This posting is an upper primary school math question on Volume and Flow Rate.

Read the posting on Sarin learns rate of change in school (Math Concept) to learn about concept of rate of change.

You can read the posting on Sarin learns Perimeter, Area and Volume in school(Math Concept) to learn the concept of volume.

Upper primary school mathematics question UPQ224

Sarin had a rectangular tank with size of 40 cm by 30 cm by 40 cm and it was 1/6 filled with water. At 0930 h, Sarin turned on the Tap X with water flowing out at a rate of 3 l per minute. At 0932 h, Sarin turned on the Tap Y to drained water out of the tank at a fixed rate.  At 0943 h, the tank was 75% filled with water. At what time would the tank be filled to the brim?

Solution:

                                                                    

                                    The capacity of the tank = 40 × 30 × 40 = 48 000 cm3

                                    The volume of water in the tank at first = 1/6 × 48 000 = 8 000 cm3

                                    From 0930h to 0943h,

                                    The time duration = 13 min

                                    The water flow rate of tap X = 3 l/min = 3000 cm3/min

                                    Water flow into the tank = 3 000 × 13 = 39 000 cm3

                                    The percentage of water in the tank at 0943h is 75%

                                    The volume of water in the tank at 0943h = 48000 × 75% = 36000 cm3

                                    The volume of water flow out = 8000 + 39000 – 36000 = 11 000 cm3

                                    The rate of water outflow from tank = 11 000 ÷ 11 = 1000 ml/min = 1 l/min

                                    The relative flow rate after 0932h = 3 – 1 = 2 l/min

                                    Another 25% capacity of the tank to fill up from 0943 h

                                    The additional volume of water needed = 48 × 25% = 12 l

                                    Require 12 ÷ 2 = 6 min more to fill up the tank to the brim

                                    At 0949 h, the tank filled to the brim 

 More Questions on Flow Rate. Click here…

More Questions on Volume. Click here…

Leave a comment