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Upper primary school mathematics question UPQ65
In the figure below, not drawn to scale, EFGH is a parallelogram. JK is a straight line and ∠ FEJ = 350. Find ∠ HEK.
EFGH is a parallelogram, FG//EH
∠ FEH = 1800 – 640 = 1160
∠ HEK = 1800 – 1160 – 350 = 290