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Upper primary school mathematics question UPQ64
In the figure below, not drawn to scale, ABC and AED are straight lines and BE = DE. Find ∠ BDC.
∠ ADC = 1800 – 380 – 720 = 700
∠ BDC = ∠ EBD = 330 (an isosceles triangle)
∠ BDC = 700 – 330 = 370