Upper primary school mathematics question UPQ2
Sarin and his mother have a total age of 100. 8 years ago, his mother’s age was 3 times that of Sarin’s age. How many years later will Sarin’s age be half that of his mother?
100 – 8*2 = 84
8 years ago, Sarin’s mother is 3 time his age. So
Sarin age is 84/4 + 8= 29 years old
And his mother is 21*3 + 8 = 71 years old
Note: When Sarin older by one year, his mother also older by one year.
Ratio of age of Sarin and his mother is 1:2 after X years
ANS: After 13 years, age of Sarin’s mother is two time of Sarin’s age.
There are 100years old in total this year
Mother = 71 years old
Sarin = 29 years old
After some years mother will be twice the age of Sarin
Draw the math model
From the model
1 unit = 71 – 29 = 42years
The number of years that mother’s age will be twice Sarin’s age = 42 – 29 = 13 years